Jeopardy James from Las Vegas will be back in January 2020 as one of the contestants in ABC's "Greatest of All Time" tournament.
Holzhauer will be competing against the show's two other biggest winners -- Ken Jennings and Brad Rutter.
The top three contestants in JEOPARDY! history will face off in an epic primetime special event: “JEOPARDY! The Greatest of All Time,” starting January 7 at 8|7c on ABC. #JeopardyGOAT pic.twitter.com/7PJUi57206
— ABC (@ABCNetwork) November 18, 2019
The tournament will begin Jan. 7, according to ABC.
Holzhauer walked away the big winner after last week's "Tournament of Champions."
Fans of the game show have often speculated on who would win between Holzhauer and Jennings. The two of them often tease each over via Twitter during Holzhauer's appearances and Holzhauer has already started with the trash talk.
— James Holzhauer (@James_Holzhauer) November 18, 2019
The tournament will consist of a series of two back-to-back games, airing weeknights beginning Jan. 7.
The player with the most combined winnings from the 2 games wins the "match," and the play continues on successive nights until one of them as won 3 matches and takes home a $1 million prize. The tournament could last anywhere from 3 to 7 days.
The other players will receive $250,000 a piece.
Holzhauer set the single-game winnings record on April 17 by winning $131,127. He won almost $2.5 million during his 32-game streak.
Jennings won $2.52 million during 72 games in 2004 and Rutter, who first played in 2000, won $4.68 million, mostly from tournaments.